49b^2=2

Solution for 49b^2=2 equation:

49b^2=2

We move all terms to the left:

49b^2-(2)=0

a = 49; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·49·(-2)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{2}}{2*49}=\frac{0-14\sqrt{2}}{98}
=-\frac{14\sqrt{2}}{98}
=-\frac{\sqrt{2}}{7}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{2}}{2*49}=\frac{0+14\sqrt{2}}{98}
=\frac{14\sqrt{2}}{98}
=\frac{\sqrt{2}}{7}
$